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PBKDF2_AES_CMAC_PRF_128 test vectors are generated using PyCryptodome library: https://github.com/Legrandin/pycryptodome Steps to generate test vectors: 1. pip install pycryptodome 2. Use the python script below to generate Derived key (see description for details): Example usage: pbkdf2_cmac.py <password> <salt> <number_of_iterations> <derived_key_len> derive_ms.py 4a30314e4d45 54687265616437333563383762344f70656e54687265616444656d6f 16384 16 password : 4a30314e4d45 salt : 54687265616437333563383762344f70656e54687265616444656d6f input cost : 16384 derived key len : 16 output : 8b27beed7e7a4dd6c53138c879a8e33c """ from Crypto.Protocol.KDF import PBKDF2 from Crypto.Hash import CMAC from Crypto.Cipher import AES import sys def main(): #check args if len(sys.argv) != 5: print("Invalid number of arguments. Expected: <password> <salt> <input_cost> <derived_key_len>") return password = bytes.fromhex(sys.argv[1]) salt = bytes.fromhex(sys.argv[2]) iterations = int(sys.argv[3]) dklen = int(sys.argv[4]) # If password is not 16 bytes then we need to use CMAC to derive the password if len(password) != 16: zeros = bytes.fromhex("00000000000000000000000000000000") cobj_pass = CMAC.new(zeros, msg=password, ciphermod=AES, mac_len=16) passwd = bytes.fromhex(cobj_pass.hexdigest()) else: passwd = password cmac_prf = lambda p,s: CMAC.new(p, s, ciphermod=AES, mac_len=16).digest() actual_output = PBKDF2(passwd, salt=salt, dkLen=dklen, count=iterations, prf=cmac_prf) print('password : ' + password.hex()) print('salt : ' + salt.hex()) print('input cost : ' + str(iterations)) print('derived key len : ' + str(dklen)) print('output : ' + actual_output.hex()) if __name__ == "__main__": main() """ Signed-off-by: Kusumit Ghoderao <Kusumit.Ghoderao@silabs.com>