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Don't reuse a variable name inside a function
Use different names for task name, a task class and a task instance. The interpreter doesn't care, but it's less confusing for both humans and type checkers. Signed-off-by: Gilles Peskine <Gilles.Peskine@arm.com>
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@ -784,17 +784,17 @@ def main():
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options = parser.parse_args()
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if options.list:
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for task in KNOWN_TASKS:
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print(task)
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for task_name in KNOWN_TASKS:
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print(task_name)
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sys.exit(0)
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if options.specified_tasks == 'all':
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tasks_list = KNOWN_TASKS.keys()
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else:
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tasks_list = re.split(r'[, ]+', options.specified_tasks)
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for task in tasks_list:
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if task not in KNOWN_TASKS:
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sys.stderr.write('invalid task: {}\n'.format(task))
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for task_name in tasks_list:
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if task_name not in KNOWN_TASKS:
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sys.stderr.write('invalid task: {}\n'.format(task_name))
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sys.exit(2)
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# If the outcome file exists, parse it once and share the result
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@ -806,22 +806,22 @@ def main():
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sys.exit(2)
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task_name = tasks_list[0]
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task = KNOWN_TASKS[task_name]
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if not issubclass(task, DriverVSReference):
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task_class = KNOWN_TASKS[task_name]
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if not issubclass(task_class, DriverVSReference):
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sys.stderr.write("please provide valid outcomes file for {}.\n".format(task_name))
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sys.exit(2)
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execute_reference_driver_tests(main_results,
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task.REFERENCE,
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task.DRIVER,
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task_class.REFERENCE,
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task_class.DRIVER,
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options.outcomes)
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outcomes = read_outcome_file(options.outcomes)
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for task_name in tasks_list:
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task_constructor = KNOWN_TASKS[task_name]
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task = task_constructor(options)
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main_results.new_section(task.section_name())
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task.run(main_results, outcomes)
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task_instance = task_constructor(options)
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main_results.new_section(task_instance.section_name())
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task_instance.run(main_results, outcomes)
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main_results.info("Overall results: {} warnings and {} errors",
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main_results.warning_count, main_results.error_count)
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