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Make format_arg() accept class hierarchies
If a base class can be formatted, it is assumed that the hierarchy can be formatted from the base class. The idiom is not uncommon with ostreams.
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doc/api.rst
30
doc/api.rst
@ -84,6 +84,36 @@ Note in the example above the ``format_arg`` function ignores the contents of
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``format_arg`` in :file:`fmt/time.h` for an advanced example of how to use
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the ``format_str`` argument to customize the formatted output.
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This technique can also be used for formatting class hierarchies::
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namespace local {
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struct Parent {
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Parent(int p) : p(p) {}
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virtual void write(fmt::Writer &w) const {
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w.write("Parent : p={}", p);
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}
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int p;
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};
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struct Child : Parent {
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Child(int c, int p) : Parent(p), c(c) {}
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virtual void write(fmt::Writer &w) const {
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w.write("Child c={} : ", c);
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Parent::write(w);
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}
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int c;
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};
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void format_arg(fmt::BasicFormatter<char> &f,
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const char *&format_str, const Parent &p) {
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p.write(f.writer());
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}
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}
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Local::Child c(1,2);
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Local::Parent &p = c;
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fmt::print("via ref to base: {}\n", p);
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fmt::print("direct to child: {}\n", c);
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This section shows how to define a custom format function for a user-defined
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type. The next section describes how to get ``fmt`` to use a conventional stream
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output ``operator<<`` when one is defined for a user-defined type.
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@ -1255,9 +1255,9 @@ inline fmt::StringRef thousands_sep(...) { return ""; }
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typedef int FMT_CONCAT_(Assert, __LINE__)[(cond) ? 1 : -1] FMT_UNUSED
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#endif
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template <typename Formatter, typename Char, typename T>
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void format_arg(Formatter &, const Char *, const T &) {
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FMT_STATIC_ASSERT(FalseType<T>::value,
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template <typename Formatter>
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void format_arg(Formatter&, ...) {
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FMT_STATIC_ASSERT(FalseType<Formatter>::value,
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"Cannot format argument. To enable the use of ostream "
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"operator<< include fmt/ostream.h. Otherwise provide "
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"an overload of format_arg.");
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