Document use of format_arg for user-defined type #393

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Victor Zverovich 2018-01-20 10:07:29 -08:00
parent c8efe145b4
commit 9649919d01

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@ -58,6 +58,43 @@ formatting::
The format string syntax is described in the documentation of
`strftime <http://en.cppreference.com/w/cpp/chrono/c/strftime>`_.
Formatting user-defined types
-----------------------------
To make a user-defined type formattable, specialize the ``formatter<T>`` struct
template and implement ``parse`` and ``format`` methods::
struct MyStruct { double x, y; };
namespace fmt {
template <>
struct formatter<MyStruct> {
template <typename ParseContext>
auto parse(ParseContext &ctx) { return ctx.begin(); }
template <typename FormatContext>
auto format(const MyStruct &s, FormatContext &ctx) {
fmt::format_to(ctx.begin(), "[MyStruct: x={:.1f}, y={:.2f}]", s.x, s.y);
}
};
}
Then you can pass objects of type ``MyStruct`` to any formatting function::
MyStruct m = {1, 2};
std::string s = fmt::format("m={}", m);
// s == "m=[MyStruct: x=1.0, y=2.00]"
In the example above the ``formatter<MyStruct>::parse`` function ignores the
contents of the format string referred to by ``ctx.begin()`` so the object will
always be formatted as specified. See ``formatter<tm>::parse`` in
:file:`fmt/time.h` for an advanced example of how to parse the format string and
customize the formatted output.
This section shows how to define a custom format function for a user-defined
type. The next section describes how to get ``fmt`` to use a conventional stream
output ``operator<<`` when one is defined for a user-defined type.
``std::ostream`` support
------------------------