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Newer versions of Python raise a SyntaxWarning when a regular expression contains a backslash that is not part of an escape sequence. To prevent this warning and future exceptions, use raw strings for all regular expressions. Even strings without escape sequences are converted for consistency. Some IDEs will apply special syntax highlighting to raw strings, which can make it easier to decipher regular expressions.
63 lines
1.7 KiB
Python
Executable File
63 lines
1.7 KiB
Python
Executable File
#!/usr/bin/env python3
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import os, sys, shutil, re, pickle, getopt
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from pathlib import Path
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def writeCodeBlock(aout, code, references):
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for function_name, url in references.items():
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html_link = '<a href="' + url + '">' + function_name + '</a>'
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#print "before:" + code + "\n\n"
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code = code.replace(function_name, html_link)
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aout.write(code)
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def main(argv):
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htmlfolder = "btstack/"
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cmd = 'html_postprocess_code_blocks.py [-o <htmlkfolder>]'
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try:
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opts, args = getopt.getopt(argv,"o:",["ofolder="])
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except getopt.GetoptError:
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print (cmd)
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sys.exit(2)
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for opt, arg in opts:
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if opt == '-h':
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print (cmd)
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sys.exit()
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elif opt in ("-o", "--ofolder"):
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htmlfolder = arg
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html_path = htmlfolder + "examples/"
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html_tmppath = htmlfolder + "examples/tmp/"
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html_in = html_path + "examples/index.html"
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html_tmp = html_tmppath + "index.html"
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references = pickle.load(open( "references.p", "rb" ))
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Path(html_tmppath).mkdir(parents=True, exist_ok=True)
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codeblock = 0
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codeblock_end = 0
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with open(html_in, 'r') as fin:
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with open(html_tmp, 'w') as fout:
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for line in fin:
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if not codeblock:
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fout.write(line)
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if re.match(r'.*<pre><code>.*',line):
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codeblock = 1
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continue
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writeCodeBlock(fout,line, references)
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# check if codeblock ended
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if re.match(r'.*</code></pre>.*',line):
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codeblock = 0
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shutil.copyfile(html_tmp, html_in)
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shutil.rmtree(html_tmppath)
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if __name__ == "__main__":
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main(sys.argv[1:])
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