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[lua] Use the correct "controller" when "tool" param is specified in app.useTool()

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Fix regression introduced in 1ec502d242ddddadf497c9738986edcaed55000b
This commit is contained in:
David Capello 2020-05-28 12:01:34 -03:00
parent 6d2ddf877b
commit 7a74aef1a7
1 changed files with 5 additions and 3 deletions
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8
src/app/script/app_object.cpp
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@ -293,15 +293,17 @@ int App_useTool(lua_State* L)
lua_pop(L, 1);
// Select tool by name
const int buttonIdx = (params.button == tools::ToolLoop::Left ? 0: 1);
auto activeToolMgr = App::instance()->activeToolManager();
params.tool = activeToolMgr->activeTool();
params.ink = params.tool->getInk(params.button == tools::ToolLoop::Left ? 0: 1);
params.controller = params.tool->getController(params.button);
params.ink = params.tool->getInk(buttonIdx);
params.controller = params.tool->getController(buttonIdx);
type = lua_getfield(L, 1, "tool");
if (type != LUA_TNIL) {
if (auto toolArg = get_tool_from_arg(L, -1)) {
params.tool = toolArg;
params.ink = params.tool->getInk(0);
params.ink = params.tool->getInk(buttonIdx);
params.controller = params.tool->getController(buttonIdx);
}
else
return luaL_error(L, "invalid tool specified in app.useTool() function");