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Tests for issue aseprite/aseprite#3207
Before the fix the conversion from RGB to INDEXED color mode, in transparent layers, always picked index 0 as transparent color, even if the mask color was present in the palette.
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@ -1,4 +1,4 @@
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-- Copyright (C) 2019-2021 Igara Studio S.A.
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-- Copyright (C) 2019-2022 Igara Studio S.A.
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--
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-- This file is released under the terms of the MIT license.
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-- Read LICENSE.txt for more information.
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@ -145,3 +145,57 @@ do
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2, 0 })
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end
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----------------------------------------------------------------------
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-- Tests for issue aseprite/aseprite#3207
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-- Conversion RGB to INDEXED color mode, in transparent layers, always
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-- picks index 0 as transparent color, even if the mask color is present
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-- in the palette.
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do
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local s = Sprite(2, 3, ColorMode.RGB)
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local p = Palette(4)
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p:setColor(0, Color(0, 0, 0))
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p:setColor(1, Color(255, 0, 0))
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p:setColor(2, Color(0, 0, 0, 0))
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p:setColor(3, Color(0, 255, 0))
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s:setPalette(p)
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local bg = s.cels[1].image
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array_to_pixels({ rgba(0, 0, 0),rgba(255, 0, 0),
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rgba(255, 0, 0), rgba(0, 0, 0, 0),
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rgba(0, 0, 0, 0), rgba(0, 0, 0, 0), }, bg)
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app.command.ChangePixelFormat{ format="indexed", rgbmap="rgb5a3" }
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-- Using the 5-bit precision of RGB5A3 will match everything with
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-- the first palette entry.
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bg = s.cels[1].image
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expect_img(bg, { 0, 1,
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1, 2,
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2, 2 })
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app.undo()
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app.command.ChangePixelFormat{ format="indexed", rgbmap="octree" }
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bg = s.cels[1].image
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expect_img(bg, { 0, 1,
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1, 2,
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2, 2 })
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app.undo()
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p:setColor(2, Color(0, 0, 255))
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s:setPalette(p)
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bg = s.cels[1].image
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app.command.ChangePixelFormat{ format="indexed", rgbmap="rgb5a3" }
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bg = s.cels[1].image
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expect_img(bg, { 2, 1,
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1, 0,
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0, 0 })
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app.undo()
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app.command.ChangePixelFormat{ format="indexed", rgbmap="octree" }
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bg = s.cels[1].image
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expect_img(bg, { 2, 1,
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1, 0,
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0, 0 })
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end
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